May 13, 2014 · 1 If a number ends with n n zeros than it is divisible by 10n 10 n, that is 2n5n 2 n 5 n. A factorial clearly has more 2 2 s than 5 5 s in its factorization so you only need to count how many 5 5 …

Jul 17, 2019 · I understand that changing the divisor multiplies the result by that, but why doesn't changing the numerator cancel that out? I found out somewhere else since posting, is there a way to …

I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight $8$'s, and parentheses. Here are the seven solutions I've found (on the Internet)...

Jan 30, 2017 · For example, the sum of all numbers less than 1000 1000 is about 500, 000 500, 000. So, 168 1000 × 500, 000 168 1000 × 500, 000 or 84, 000 84, 000 should be in the right ballpark. …

Oct 19, 2025 · Therefore there are exactly $1000$ squares between the successive cubes $ (667^2)^3$ and $ (667^2+1)^3$, or between $444889^3$ and $444890^3$. Finally, we can verify all of this by …

Dec 15, 2019 · The number of random number generations is 1000 1000 plus the expected number of collisions, so minimizing the number of collisions is equivalent to minimizing the number of random …

Aug 23, 2015 · I'm trying to solve the following exercise: $$2017^ {2016^ {2015}} \mod 1000,$$ here's what I've already come up with: Using Euler's conrgruence, one finds that $$2017^ {2016^ {2015}} …

Oct 3, 2023 · The number of bacteria in a culture is 1000 and this number increases by 250% every two hours. How many bacteria is present after 24 hours?

Find the sum of all the multiples of 3 or 5 below 1000 (Break down) Ask Question Asked 11 years, 2 months ago Modified 3 years, 7 months ago

Jan 1, 2018 · The of 210 210 - the number of values between 1 1 and 210 210 that are relatively prime to 210 210 - is (2 − 1)(3 − 1)(5 − 1)(7 − 1) = 48 (2 1) (3 1) (5 1) (7 1) = 48. Using this, we can say that …