A 2.667-g sample containing both Fe and V was dissolved under conditions that converted the elements to Fe (III) and V(V). The solution was diluted to 500.0  mL, and a 50.00-mL aliquot was passed through a Walden reductor and titrated with 18.31  mL of 0.1000 M Ce^4 . A second 50.00-mL aliquot was passed through a Jones reductor and required 42.41  mL of the same Ce^4 solution to reach an end point. Calculate the percentage of Fe2 O3 and V2 O5 in the sample. | Numerade